$\left(3m^5n^3-5m^3n^2\right)^2$
$\:21\left(3x\right)^3\left(y\right)^4$
$-28+\left(-0\right)-\left(-20\right)$
$5x-8x+3x<\:17$
$2^{2x-4}=16$
$\frac{x^{2}-28}{x-5}$
$4tan\left(x\right)-3=1$
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