$\tan\left(x\right)\sin\left(x\right)+\cos\left(x\right)=2\tan\left(x\right)$

$n^3=1$

$-5+19-\frac{16}{4}$

$\frac{\sin x\:-\:\sin\:3\:x\:}{\sin^2x-\cos^2x}=\:2\sin x$

$\left(3z-2y^2\right)^4$

$6.9=\tan\left(24\right)-\left(4.9\cdot\left(\frac{24}{18.121\cdot\cos\left(x\right)}\right)\right)$

$140+21$